HomeNCERT SOLUTIONS8th CLASSClass 8 Maths Chapter 4 Practical Geometry Solutions

Class 8 Maths Chapter 4 Practical Geometry Solutions

Practical-Geometry

Advertisement

NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.1

Ex 4.1 Class 8 Maths Question 1.
Construct the following quadrilaterals.
(i) Quadrilateral ABCD
AB = 4.5 cm, BC = 5.5 cm, CD = 4 cm, AD = 6 cm, AC = 7 cm
(ii) Quadrilateral JUMP
JU = 3.5 cm, UM = 4 cm, MP = 5 cm, PJ = 4.5 cm, PU = 6.5 cm
(iii) Parallelogram MORE
OR = 6 cm, RE = 4.5 cm, EO = 7.5 cm
(iv) Rhombus BEST
BE = 4.5 cm, ET = 6 cm
Solution:
(i) We have to draw first rough sketch.
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry
Construction:
Step I: Draw AB = 4.5 cm
Step II: Draw an arc with centre B and radius 5.5 cm.
Step III: Draw another arc with centre A and radius 7 cm to meet the previous arc at C.
Step IV: Draw an arc with centre C and radius 4 cm.
Step V: Draw another arc with centre A and radius 6 cm to cut the former arc at D.
Step VI: Join BC, AC, CD and AD.
(ii) We have to draw the first rough sketch.
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry
Thus ABCD is the required quadrilateral.
Construction:
Step I: Draw JU = 3.5 cm.
Step II: Draw an arc with centre J and radius 4.5 cm.
Step III: Draw another arc with centre U and radius 6.5 cm to meet the previous arc at P.
Step IV: Join JP and UP.
Step V: Draw an arc with centre U and radius 4 cm.
Step VI: Draw another arc with centre P and radius 5 cm to meet the previous arc at M.
Step VII: Join UM and PM.
Thus, JUMP is the required quadrilateral.
(iii) We have to draw the first rough sketch.
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry
Construction: (Opposite sides of a parallelogram are equal)
Step I: Draw OR = 6 cm.
Step II: Draw an arc with centre R and radius 4.5 cm.
Step III: Draw another arc with centre O and radius 7.5 cm to meet the previous arc at E.
Step IV: Join RE and OE.
Step V: Draw an arc with centre E and radius 6 cm.
Step VI: Draw another arc with centre O and radius 4.5 cm to meet the former arc at M.
Step VII: Join EM and OM.
Thus, MORE is the required parallelogram.
(iv) We have to draw first rough sketch.
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry
Construction: (All sides of a rhombus are equal)
Step I: Draw BE = 4.5 cm
Step II: Draw an arc with centre B and radius 4.5 cm.
Step III: Draw another arc with centre E and radius 6 cm to meet the previous arc at T.
Step IV: Join BT and ET.
Step V: Draw two arcs with centres E and T with equal radii 4-5 cm to meet each other at S. .
Step VI: Join ES and TS.
Thus, BEST is the required rhombus.

ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-1-q-1
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-1-q-2
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-1-q-3
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-1-q-4
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-1-q-5

Class 8 Maths Chapter 4 Practical Geometry Ex 4.2 Solutions

NCERT Class 8 Maths Chapter 4 Practical Geometry Ex 4.2 Solutions

NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.2

Advertisement

Ex 4.2 Class 8 Maths Question 1.
Construct the following quadrilaterals.
(i) Quadrilateral LIFT
LI = 4 cm
IF = 3 cm
TL = 2.5 cm
LF = 4.5 cm
IT = 4 cm
(ii) Quadrilateral GOLD
OL = 7.5 cm
GL = 6 cm
GD = 6 cm
LD = 5 cm
OD = 10 cm
(iii) Rhombus BEND
BN = 5.6 cm
DE = 6.5 cm
Solution:
(i) Construction:
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2 Q1
Step I: Draw LI = 4 cm.
Step II: Draw an arc with centre I and radius 3 cm.
Step III: Draw another arc with centre L and radius 4.5 cm to meet the former arc at F.
Step IV: Join LF and IF.
Step V: Draw an arc with centre L and radius 2.5 cm.
Step VI: Draw another arc with centre I and radius 4 cm to meet the previous arc at T.
Step VII: Join LT and IT.
Thus LIFT is the required quadrilateral.
(ii) Construction:
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2 Q1.1
Step I: Draw OL = 7.5 cm
Step II: Draw an arc with centre O and radius 10 cm.
Step III: Draw another arc with centre L and radius 5 cm to meet the previous arc at D.
Step IV: Join OD and LD.
Step V: Draw an arc with centre L and D with equal radii of 6 cm to meet each other at G.
Step VI: Join LG and DG.
Thus GOLD is the required quadrilateral.
(iii) Construction: (The diagonals of a rhombus bisect each other at the right angle)
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2 Q1.2
Step I: Draw BN = 5.6 cm.
Step II: Draw the right bisector of BN at O.
Step III: Draw two arcs with centre O and radius \frac { 1 }{ 2 } × DE, i.e., \frac { 1 }{ 2 } × 6.5 = 3.25 cm to meet the right bisector at D and E.
Step IV: Join BE, EN, ND and BD.
Thus, BEND is the required rhombus.

Advertisement
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-2-q-1
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-2-q-2
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-2-q-3
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-2-q-4
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-2-q-5

Class 8 Maths Chapter 4 Practical Geometry Ex 4.3 Solutions

NCERT Class 8 Maths Chapter 4 Practical Geometry Ex 4.3 Solutions

NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.3

Ex 4.3 Class 8 Maths Question 1.
Construct the following quadrilaterals:
(i) Quadrilateral MORE
MO = 6 cm, ∠R = 105°, OR = 4.5 cm, ∠M = 60°, ∠O = 105°
(ii) Quadrilateral PLAN
PL = 4 cm, LA = 6.5 cm, ∠P = 90°, ∠A = 110°, ∠N = 85°
(iii) Parallelogram HEAR
HE = 5 cm, EA = 6 cm, ∠R = 85°
(iv) Rectangle OKAY
OK = 7 cm, KA = 5 cm
Solution:
(i) Construction:
Step I: Draw OR = 4.5 cm
Step II: Draw two angles of 105° each at O and R with the help of protactor.
Step III: Cut OM = 6 cm.
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.3 Q1
Step IV: Draw an angle of 60° at M to meet the angle line through R at E.
Thus, MORE is the required quadrilateral.

Advertisement

(ii) Construction:
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.3 Q1.1
Step I: Draw LA = 6.5 cm
Step II: Draw an angle of 75° at L and 110° at A with the help of a protractor.
[∵ 360° – (110° + 90° + 85°) = 75°]
Step III: Cut LP = 4 cm.
Step IV: Draw an angle of 90° at P which meets the angle line through A at N.
Thus PLAN is the required quadrilateral.

Advertisement

(iii) Construction: (Opposite sides of a parallelogram are equal)
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.3 Q1.2
Step I: Draw HE = 5 cm.
Step II: Draw an angle of 85° at E and cut EA = 6 cm.
Step III: Draw an arc with centre A and radius 5 cm.
Step IV: Draw another arc with centre H and radius 6 cm to meet the previous arc at R.
Step V: Join HR and AR
Thus, HEAR is the required parallelogram.

(iv) Construction:
(Each angle of a rectangle is 90° and opposite sides are equal.)
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.3 Q1.3
Step I: Draw OK = 7 cm.
Step II: Draw the angle of 90° at K and cut KA = 5 cm.
Step III: Draw an arc with centre O and radius 5 cm.
Step IV: Draw another arc with centre A and radius 7 cm to meet the previous arc at Y.
Step V: Join OY and AY.
Thus OKAY is the required rectangle.

Advertisement

ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-3-q-1
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-3-q-2
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-3-q-3
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-3-q-4
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-3-q-5
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-3-q-6
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-3-q-7

Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 Solutions

NCERT Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 Solutions

NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.4

Advertisement

Ex 4.4 Class 8 Maths Question 1.
Construct the following quadrilaterals:
(i) Quadrilateral DEAR
DE = 4 cm, EA = 5 cm, AR = 4.5 cm, ∠E = 60°, ∠A = 90°
(ii) Quadrilateral TRUE
TR = 3.5 cm, RU = 3 cm, UE = 4.5 cm, ∠R = 75°, ∠U = 120°
Solution:
(i) Construction:
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 Q1
Step I: Draw DE = 4 cm.
Step II: Draw an angle of 60° at E.
Step III: Draw an arc with centre E and radius 5 cm to meet the angle line at A.
Step IV: Draw an angle of 90° at A and cut AR = 4.5 cm.
Step V: Join DR.
Thus, DEAR is the required quadrilateral.

(ii) Construction:
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 Q1.2
Step I: Draw TR = 3.5 cm
Step II: Draw an angle of 75° at R and cut RU = 3 cm.
Step III: Draw an angle of 120° at U and cut UE = 4.5 cm.
Step IV: Join TE.
Thus, TRUE is the required quadrilateral.

Advertisement

ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-4-q-1
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-4-q-2
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-4-q-3
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-4-q-4

Class 8 Maths Chapter 4 Practical Geometry Ex 4.5 Solutions

NCERT Class 8 Maths Chapter 4 Practical Geometry Ex 4.5 Solutions

NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.5

Advertisement

Draw the following:
Ex 4.5 Class 8 Maths Question 1.
The square READ with RE = 5.1 cm.
Solution:
Construction:
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.5 Q1
Step I: Draw RE = 5.1 cm.
Step II: Draw an angle of 90° at E and cut EA = 5.1 cm.
Step III: Draw two arcs from A and R with radius 5.1 cm to cut each other at D.
Step IV: Join RD and AD.
Thus, READ is the required square.

Ex 4.5 Class 8 Maths Question 2.
A rhombus whose diagonals are 5.2 cm and 6.4 cm long.
Solution:
Construction:
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.5 Q2
Step I: Draw AC = 6.4 cm.
Step II: Draw the right bisector of AC at E.
Step III: Draw two arcs with centre E and radius = \frac { 5.2 }{ 2 } = 2.6 cm to cut the previous diagonal at B and D.
Step IV: Join AD, AB, BC and DC.
Thus ABCD is the required rhombus.

Ex 4.5 Class 8 Maths Question 3.
A rectangle with adjacent sides of lengths 5 cm and 4 cm.
Solution:
Construction: Let the two adjacent sides of a rectangle PQRS be PQ = 5 cm and QR = 4 cm.
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.5 Q3
Step I: Draw PQ = 5 cm.
Step II: Draw an angle of 90° at Q and cut QR = 4 cm.
Step III: Draw an arc with centre R and radius 5 cm.
Step IV: Draw another arc with centre P and radius 4 cm to meet the previous arc at S.
Step V: Join RS and PS.
Thus, PQRS is the required rectangle.

Ex 4.5 Class 8 Maths Question 4.
A parallelogram OKAY where OK = 5.5 cm and KA = 4.2 cm. Is it unique?
Solution:
Construction:
Step I: Draw OK = 5.5 cm.
Step II: Draw an angle of any measure (say 60°) at K and cut KA = 4.2 cm.
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.5 Q4
Step III: Draw an arc with centre A and radius of 5.5 cm.
Step IV: Draw another arc with centre O and radius 4.2 cm to cut the previous arc at Y.
Step V: Join AY and OY.
Thus, OKAY is the required parallelogram.
No, it is not a unique parallelogram. The angle at K can be of measure other than 60°.

ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-5-q-1
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-5-q-2
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-5-q-3
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-5-q-4
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-5-q-5
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-5-q-6
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-5-q-7
ncert-solutions-for-class-8-maths-chapter-4-practical-geometry-ex-4-5-q-8

Extra Questions

Practical Geometry Class 8 Extra Questions Maths Chapter 4

Extra Questions for Class 8 Maths Chapter 4 Practical Geometry

Question 1.
Construct a quadrilateral PQRS, given that QR = 4.5 cm, PS = 5.5 cm, RS = 5 cm and the diagonal PR = 5.5 cm and diagonal SQ = 7 cm.
Practical Geometry NCERT Extra Questions for Class 8 Maths Q1
Solution:
Construction:
Step I: Draw QR = 4.5 cm.
Step II: Draw an arc with centre R and radius 5 cm.
Step III: Draw another arc with centre Q and radius 7 cm to meet the previous arc at S.
Step IV: Join RS and QS.
Step V: Draw two arcs with centre S and R and radius 5.5 cm each to meet each other at P.
Step VI: Join RP, SP and PQ.
Thus PQRS is the required quadrilateral.

Question 2.
Construct a quadrilateral ABCD in which AB = 4 cm, BC = 3.5 cm, CD = 5 cm, AD = 5.5 cm and ∠B = 75°.
Practical Geometry NCERT Extra Questions for Class 8 Maths Q2
Solution:
Construction:
Step I: Draw AB = 4 cm.
Step II: Draw an angle of 75° at B and cut BC = 3.5 cm.
Step III: Draw an arc with centre C and radius 5 cm.
Step IV: Draw another arc with centre A and radius 5.5 cm to meet the previous arc at D.
Step V: Join CD and AD.
Thus ABCD is the required quadrilateral.

Question 3.
Construct a square whose side is 5 cm.
Practical Geometry NCERT Extra Questions for Class 8 Maths Q3
Solution:
Construction:
Step I: Draw AB = 5 cm.
Step II: Draw an angle of 90° at B and cut BC = 5 cm.
Step III: Draw two arcs with centre A and C and same radii of 5 cm which meet each other at D.
Step IV: Join AD and CD.
Thus, ABCD is the required square.

Question 4.
Construct a rhombus ABCD in which AB = 5.8 cm and AC = 7.5 cm.
Practical Geometry NCERT Extra Questions for Class 8 Maths Q4
Solution:
Construction:
Step I: Draw AB = 5.8 cm.
Step II: Draw an arc with centre B and radius 5.8 cm.
Step III: Draw another arc with centre A and radius 7.5 cm to meet the previous arc at C.
Step IV: Draw two arcs with centres A and C and of the same radius 5.8 cm to meet each other at D.
Step V: Join BC, AC, CD and AD.
Thus ABCD is the required rhombus.

Question 5.
Construct a rhombus whose diagonals are 6 cm and 8 cm.
Practical Geometry NCERT Extra Questions for Class 8 Maths Q5
Solution:
Construction:
Step I: Draw SQ = 8 cm.
Step II: Draw a right bisector of SQ at O.
Step III: Draw two arcs with centre O and radius 3 cm each to cut the right bisector at P and R.
Step TV: Join PQ, QR, RS and SP.
Thus PQRS is the required rhombus.

Question 6.
Construct a rectangle whose diagonal is 5 cm and the angle between the diagonal is 50°.
Practical Geometry NCERT Extra Questions for Class 8 Maths Q6
Practical Geometry NCERT Extra Questions for Class 8 Maths Q6.1
Solution:
Construction:
Step I: Draw AC = 5 cm.
Step II: Draw the right bisector of AC at O.
Step III: Draw an angle of 50° at O and product both sides.
Step IV: Draw two arcs with centre O and of the same radius 2.5 cm to cut at B and D.
Step V: Join AB, BC, CD and DA.
Thus, ABCD is the required rectangle.

Question 7.
Construct a quadrilateral ABCD in which BC = 4 cm, ∠B = 60°, ∠C = 135°, AB = 5 cm and ∠A = 90°.
Practical Geometry NCERT Extra Questions for Class 8 Maths Q7
Solution:
Construction:
Step I: Draw AB = 5 cm.
Step II: Draw the angle of 60° at B and cut BC = 4 cm.
Step III: Draw an angle of 135° at C and angle of 90° at A which meet each other at D.
Thus, ABCD is the required quadrilateral.

Question 8.
Construct a parallelogram ABCD in which AB = 5.5 cm, AC = 7 cm and BD = 8 cm.
Practical Geometry NCERT Extra Questions for Class 8 Maths Q8
Solution:
Construction:
Step I: Draw AB = 5.5 cm.
Step II: Draw an arc with centre B and radius \frac { 8 }{ 2 } cm = 4 cm.
Step III: Draw another arc with centre A and radius \frac { 7 }{ 2 } cm = 3.5 cm which cuts the previous arc at O.
Step IV: Join AO and produce to C such that AO = OC.
Step V: Join BO and produce to D such that BO = OD.
Step VI: Join BC, CD and AD.
Thus ABCD is the required parallelogram.

Question 9.
Construct a rhombus PAIR, given that PA = 6 cm and angle ∠A = 110°.
Solution:
Since in a rhombus, all sides are equal, so PA = AI = IR = RP = 6 cm
Also, rhombus is a parallelogram
so, adjacent angle, ∠I = 180° – 110° = 70°
Practical Geometry NCERT Extra Questions for Class 8 Maths Q9
Steps of construction
Step I. Draw AI = 6 cm
Step II. Draw ray \bar { AX } such that ∠IAX = 110° and draw \bar { IY } such that ∠AIY = 70°.
Step III. With A and I as centres and radius 6 cm draw arcs intersecting AX and IY at P and R respectively.
Step IV. Join PR.
Thus, PAIR is the required rhombus.

practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-01
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-02
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-03
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-04
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-05
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-06
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-07
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-08
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-09
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-10
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-11
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-12
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-13
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-14
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-15
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-16
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-17
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-18
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-19
practical-geometry-ncert-extra-questions-for-class-8-maths-chapter-4-20

NCERT Solutions for Class 8 Maths

RECENT POSTS

DAILY TESTS

CURRENT AFFAIRS

రివిజన్ నోట్స్

తెలంగాణ పాటలు‌‌ రచయితలు: రివిజన్​ నోట్స్ 5

పల్లెటూరి పిల్లగాడపసులకాడి మొనగాడపాలుమరచి ఎన్నాళ్లయిందోఓ…. పాలబుగ్గల జీతగాడా!!!సుద్దాల హన్మంతుబండెనక బండి గట్టి - పదహారెడ్లబండికట్టిబండి యాదగిరి:రాజిగ - ఓ రాజిగ పుడితె ఒకడుచస్తే రెండుఊరు మనదిరా వాడమనదిరాగూడ అంజన్న. ఇద్దరం విడిపోతే భూమిబద్దలవుతుందా…'పల్లె...

తెలంగాణ ఉద్యమం నాటి పుస్తకాలు – రచయితలు : రివిజన్​ నోట్స్ 4

ఉద్యమం నాటి పుస్తకాలు - రచయితలు తెలంగాణ రాష్ట్రం ఒక డిమాండ్​ ప్రొఫెసర్​ జయశంకర్​తెలంగాణలో ఏం జరుగుతోందిప్రొఫెసర్​ జయశంకర్​'ఎ రిబట్టర్ టు విశాలాంధ్ర గోబెల్స్ ప్రాపగండ' కొణతం దిలిప్ తెలంగాణ విద్యతెలంగాణ విద్యావంతుల...

నిజాం కాలం నాటి ముఖ్య పత్రికలు… తెలంగాణ రివిజన్​ నోట్స్ 3

పోటీ పరీక్షలకు ప్రిపేరయ్యే అభ్యర్థుల ఉపయోగం కొరకు తెలంగాణ చరిత్రకు సంబంధించి కొన్ని ముఖ్యాంశాలు అందిస్తున్నాం. కొన్నింటిని చారిత్రక క్రమంలో పట్టిక రూపంలో ఇవ్వడం జరిగింది. పరీక్షలలో ప్రశ్నలు అడిగే విధానాన్ని దృష్టిలో...

తెలంగాణ ఉద్యమం‌‌.. చరిత్ర.. సంస్కృతి రివిజన్​ నోట్స్ 2

పోటీ పరీక్షలకు ప్రిపేరయ్యే అభ్యర్థుల ఉపయోగం కొరకు తెలంగాణ చరిత్రకు సంబంధించి కొన్ని ముఖ్యాంశాలు అందిస్తున్నాం. కొన్నింటిని చారిత్రక క్రమంలో పట్టిక రూపంలో ఇవ్వడం జరిగింది. పరీక్షలలో ప్రశ్నలు అడిగే విధానాన్ని దృష్టిలో...

తెలంగాణ ఉద్యమం‌‌.. చరిత్ర.. సంస్కృతి రివిజన్​ నోట్స్ 1

పోటీ పరీక్షలకు ప్రిపేరయ్యే అభ్యర్థుల ఉపయోగం కొరకు తెలంగాణ చరిత్రకు సంబంధించి కొన్ని ముఖ్యాంశాలు అందిస్తున్నాం. కొన్నింటిని చారిత్రక క్రమంలో పట్టిక రూపంలో ఇవ్వడం జరిగింది. పరీక్షలలో ప్రశ్నలు అడిగే విధానాన్ని దృష్టిలో...

భక్తి.. సూఫీ ఉద్యమాలు

భక్తి, సూఫీ ఉద్యమాల నుంచి అన్ని పోటీ పరీక్షల్లో ప్రశ్నలు అడుగుతున్నారు. అందుకే అభ్యర్థుల ప్రిపరేషన్​కు ఉపయోగపడే విధంగా రన్నింగ్​ నోట్స్​ ఇక్కడ అందిస్తున్నం.శంకరాచార్యులు, రామానుజాచార్యులు, మధ్వాచార్యలను త్రిమతాచార్యులు అంటారు. వీరి రాకతో...

భారత దేశ సరిహద్దులు.. సంబంధాలు

పోటీ పరీక్షల్లో ఇండియన్​ జాగ్రఫీ కీలకం. అందులో భారత ఉనికి.. స్వరూపం నుంచి ఎక్కువగా ప్రశ్నలు వచ్చే అవకాశముంటుంది. సరిహద్దులు.. ఇరుగు పొరుగు దేశాలతో ఉన్న సంబంధాలు, వివాదాలపై తప్పనిసరి ప్రశ్నలు అడిగే...

తెలంగాణ ప్రభుత్వ పథకాలు

తెలంగాణకు హరితహారం: రాష్ట్రంలో ఉన్న అటవీ విస్తీర్ణంలో 24 శాతం నుంచి 33శాతానికి పెంచాలనే ఉద్దేశ్యంతో ప్రారంభించిన కార్యక్రమం ‘కోతులు వాపస్​ పోవాలి వానలు వాపస్​ రావాలె’ అనే నినాదంతో 2015 జులై...

భారతదేశంలో బ్రిటీష్ గవర్నర్​ జనరల్స్​

వారన్​ హేస్టింగ్స్​ 1772 నుంచి 1774 వరకు బెంగాల్​ చివరి గవర్నర్ గా పనిచేశారు. 1774 నుంచి ఈస్ట్​ ఇండియా కంపెనీటి మొదటి గవర్నర్​ జనరల్​ లేదా తొలి గవర్నర్​ జనరల్​...

తెలంగాణ ఉద్యమ సంస్థలు.. రాజకీయ పార్టీలు

1983 తెలంగాణ డెమోక్రటిక్​ ఫ్రంట్​ సత్యనారాయణ1985 ఫిబ్రవరి 27 తెలంగాణ జనసభ దుశ్చర్ల సత్యనారాయణ1987 తెలంగాణ ప్రజా సమితి భూపతి కృష్ణమూర్తి1989 తెలంగాణ పోరాట సమితి కె.ఆర్.​ ఆమోస్​, మేచినేని కిషన్​రావు1990 తెలంగాణ...

తెలంగాణ రాష్ట్ర సాధన.. ముఖ్యమైన కమిటీలు

అయ్యంగార్​ కమిటీ: హైదరాబాద్​ రాజ్యంలో రాజ్యాంగ సంస్కరణల కోసం 1937లో ఏడో నిజాం మీర్​ ఉస్మాన్​ అలీఖాన్​ ఈ కమిటీని నియమించాడు.ఎం.ఎస్​.భరూచ కమిటీ: నిజాం రాజ్యంలో కౌలుదారుల స్థితిగతులు పరిశీలించుటకు 1939లో ఈ...

LEAVE A REPLY

Please enter your comment!
Please enter your name here

RECENT POSTS

x
error: Content is protected !!