**NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.1**

Ex 4.1 Class 8 Maths Question 1.

Construct the following quadrilaterals.

(i) Quadrilateral ABCD

AB = 4.5 cm, BC = 5.5 cm, CD = 4 cm, AD = 6 cm, AC = 7 cm

(ii) Quadrilateral JUMP

JU = 3.5 cm, UM = 4 cm, MP = 5 cm, PJ = 4.5 cm, PU = 6.5 cm

(iii) Parallelogram MORE

OR = 6 cm, RE = 4.5 cm, EO = 7.5 cm

(iv) Rhombus BEST

BE = 4.5 cm, ET = 6 cm

Solution:

(i) We have to draw first rough sketch.

Construction:

Step I: Draw AB = 4.5 cm

Step II: Draw an arc with centre B and radius 5.5 cm.

Step III: Draw another arc with centre A and radius 7 cm to meet the previous arc at C.

Step IV: Draw an arc with centre C and radius 4 cm.

Step V: Draw another arc with centre A and radius 6 cm to cut the former arc at D.

Step VI: Join BC, AC, CD and AD.

(ii) We have to draw the first rough sketch.

Thus ABCD is the required quadrilateral.

Construction:

Step I: Draw JU = 3.5 cm.

Step II: Draw an arc with centre J and radius 4.5 cm.

Step III: Draw another arc with centre U and radius 6.5 cm to meet the previous arc at P.

Step IV: Join JP and UP.

Step V: Draw an arc with centre U and radius 4 cm.

Step VI: Draw another arc with centre P and radius 5 cm to meet the previous arc at M.

Step VII: Join UM and PM.

Thus, JUMP is the required quadrilateral.

(iii) We have to draw the first rough sketch.

Construction: (Opposite sides of a parallelogram are equal)

Step I: Draw OR = 6 cm.

Step II: Draw an arc with centre R and radius 4.5 cm.

Step III: Draw another arc with centre O and radius 7.5 cm to meet the previous arc at E.

Step IV: Join RE and OE.

Step V: Draw an arc with centre E and radius 6 cm.

Step VI: Draw another arc with centre O and radius 4.5 cm to meet the former arc at M.

Step VII: Join EM and OM.

Thus, MORE is the required parallelogram.

(iv) We have to draw first rough sketch.

Construction: (All sides of a rhombus are equal)

Step I: Draw BE = 4.5 cm

Step II: Draw an arc with centre B and radius 4.5 cm.

Step III: Draw another arc with centre E and radius 6 cm to meet the previous arc at T.

Step IV: Join BT and ET.

Step V: Draw two arcs with centres E and T with equal radii 4-5 cm to meet each other at S. .

Step VI: Join ES and TS.

Thus, BEST is the required rhombus.

# Class 8 Maths Chapter 4 Practical Geometry Ex 4.2 Solutions

## NCERT Class 8 Maths Chapter 4 Practical Geometry Ex 4.2 Solutions

**NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.2**

Ex 4.2 Class 8 Maths Question 1.

Construct the following quadrilaterals.

(i) Quadrilateral LIFT

LI = 4 cm

IF = 3 cm

TL = 2.5 cm

LF = 4.5 cm

IT = 4 cm

(ii) Quadrilateral GOLD

OL = 7.5 cm

GL = 6 cm

GD = 6 cm

LD = 5 cm

OD = 10 cm

(iii) Rhombus BEND

BN = 5.6 cm

DE = 6.5 cm

Solution:

(i) Construction:

Step I: Draw LI = 4 cm.

Step II: Draw an arc with centre I and radius 3 cm.

Step III: Draw another arc with centre L and radius 4.5 cm to meet the former arc at F.

Step IV: Join LF and IF.

Step V: Draw an arc with centre L and radius 2.5 cm.

Step VI: Draw another arc with centre I and radius 4 cm to meet the previous arc at T.

Step VII: Join LT and IT.

Thus LIFT is the required quadrilateral.

(ii) Construction:

Step I: Draw OL = 7.5 cm

Step II: Draw an arc with centre O and radius 10 cm.

Step III: Draw another arc with centre L and radius 5 cm to meet the previous arc at D.

Step IV: Join OD and LD.

Step V: Draw an arc with centre L and D with equal radii of 6 cm to meet each other at G.

Step VI: Join LG and DG.

Thus GOLD is the required quadrilateral.

(iii) Construction: (The diagonals of a rhombus bisect each other at the right angle)

Step I: Draw BN = 5.6 cm.

Step II: Draw the right bisector of BN at O.

Step III: Draw two arcs with centre O and radius × DE, i.e., × 6.5 = 3.25 cm to meet the right bisector at D and E.

Step IV: Join BE, EN, ND and BD.

Thus, BEND is the required rhombus.

# Class 8 Maths Chapter 4 Practical Geometry Ex 4.3 Solutions

## NCERT Class 8 Maths Chapter 4 Practical Geometry Ex 4.3 Solutions

**NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.3**

Ex 4.3 Class 8 Maths Question 1.

Construct the following quadrilaterals:

(i) Quadrilateral MORE

MO = 6 cm, ∠R = 105°, OR = 4.5 cm, ∠M = 60°, ∠O = 105°

(ii) Quadrilateral PLAN

PL = 4 cm, LA = 6.5 cm, ∠P = 90°, ∠A = 110°, ∠N = 85°

(iii) Parallelogram HEAR

HE = 5 cm, EA = 6 cm, ∠R = 85°

(iv) Rectangle OKAY

OK = 7 cm, KA = 5 cm

Solution:

(i) Construction:

Step I: Draw OR = 4.5 cm

Step II: Draw two angles of 105° each at O and R with the help of protactor.

Step III: Cut OM = 6 cm.

Step IV: Draw an angle of 60° at M to meet the angle line through R at E.

Thus, MORE is the required quadrilateral.

(ii) Construction:

Step I: Draw LA = 6.5 cm

Step II: Draw an angle of 75° at L and 110° at A with the help of a protractor.

[∵ 360° – (110° + 90° + 85°) = 75°]

Step III: Cut LP = 4 cm.

Step IV: Draw an angle of 90° at P which meets the angle line through A at N.

Thus PLAN is the required quadrilateral.

(iii) Construction: (Opposite sides of a parallelogram are equal)

Step I: Draw HE = 5 cm.

Step II: Draw an angle of 85° at E and cut EA = 6 cm.

Step III: Draw an arc with centre A and radius 5 cm.

Step IV: Draw another arc with centre H and radius 6 cm to meet the previous arc at R.

Step V: Join HR and AR

Thus, HEAR is the required parallelogram.

(iv) Construction:

(Each angle of a rectangle is 90° and opposite sides are equal.)

Step I: Draw OK = 7 cm.

Step II: Draw the angle of 90° at K and cut KA = 5 cm.

Step III: Draw an arc with centre O and radius 5 cm.

Step IV: Draw another arc with centre A and radius 7 cm to meet the previous arc at Y.

Step V: Join OY and AY.

Thus OKAY is the required rectangle.

# Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 Solutions

## NCERT Class 8 Maths Chapter 4 Practical Geometry Ex 4.4 Solutions

**NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.4**

Ex 4.4 Class 8 Maths Question 1.

Construct the following quadrilaterals:

(i) Quadrilateral DEAR

DE = 4 cm, EA = 5 cm, AR = 4.5 cm, ∠E = 60°, ∠A = 90°

(ii) Quadrilateral TRUE

TR = 3.5 cm, RU = 3 cm, UE = 4.5 cm, ∠R = 75°, ∠U = 120°

Solution:

(i) Construction:

Step I: Draw DE = 4 cm.

Step II: Draw an angle of 60° at E.

Step III: Draw an arc with centre E and radius 5 cm to meet the angle line at A.

Step IV: Draw an angle of 90° at A and cut AR = 4.5 cm.

Step V: Join DR.

Thus, DEAR is the required quadrilateral.

(ii) Construction:

Step I: Draw TR = 3.5 cm

Step II: Draw an angle of 75° at R and cut RU = 3 cm.

Step III: Draw an angle of 120° at U and cut UE = 4.5 cm.

Step IV: Join TE.

Thus, TRUE is the required quadrilateral.

# Class 8 Maths Chapter 4 Practical Geometry Ex 4.5 Solutions

## NCERT Class 8 Maths Chapter 4 Practical Geometry Ex 4.5 Solutions

**NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.5**

**Draw the following:**

Ex 4.5 Class 8 Maths Question 1.

The square READ with RE = 5.1 cm.

Solution:

Construction:

Step I: Draw RE = 5.1 cm.

Step II: Draw an angle of 90° at E and cut EA = 5.1 cm.

Step III: Draw two arcs from A and R with radius 5.1 cm to cut each other at D.

Step IV: Join RD and AD.

Thus, READ is the required square.

Ex 4.5 Class 8 Maths Question 2.

A rhombus whose diagonals are 5.2 cm and 6.4 cm long.

Solution:

Construction:

Step I: Draw AC = 6.4 cm.

Step II: Draw the right bisector of AC at E.

Step III: Draw two arcs with centre E and radius = = 2.6 cm to cut the previous diagonal at B and D.

Step IV: Join AD, AB, BC and DC.

Thus ABCD is the required rhombus.

Ex 4.5 Class 8 Maths Question 3.

A rectangle with adjacent sides of lengths 5 cm and 4 cm.

Solution:

Construction: Let the two adjacent sides of a rectangle PQRS be PQ = 5 cm and QR = 4 cm.

Step I: Draw PQ = 5 cm.

Step II: Draw an angle of 90° at Q and cut QR = 4 cm.

Step III: Draw an arc with centre R and radius 5 cm.

Step IV: Draw another arc with centre P and radius 4 cm to meet the previous arc at S.

Step V: Join RS and PS.

Thus, PQRS is the required rectangle.

Ex 4.5 Class 8 Maths Question 4.

A parallelogram OKAY where OK = 5.5 cm and KA = 4.2 cm. Is it unique?

Solution:

Construction:

Step I: Draw OK = 5.5 cm.

Step II: Draw an angle of any measure (say 60°) at K and cut KA = 4.2 cm.

Step III: Draw an arc with centre A and radius of 5.5 cm.

Step IV: Draw another arc with centre O and radius 4.2 cm to cut the previous arc at Y.

Step V: Join AY and OY.

Thus, OKAY is the required parallelogram.

No, it is not a unique parallelogram. The angle at K can be of measure other than 60°.

# Extra Questions

## Practical Geometry Class 8 Extra Questions Maths Chapter 4

**Extra Questions for Class 8 Maths Chapter 4 Practical Geometry**

Question 1.

Construct a quadrilateral PQRS, given that QR = 4.5 cm, PS = 5.5 cm, RS = 5 cm and the diagonal PR = 5.5 cm and diagonal SQ = 7 cm.

Solution:

Construction:

Step I: Draw QR = 4.5 cm.

Step II: Draw an arc with centre R and radius 5 cm.

Step III: Draw another arc with centre Q and radius 7 cm to meet the previous arc at S.

Step IV: Join RS and QS.

Step V: Draw two arcs with centre S and R and radius 5.5 cm each to meet each other at P.

Step VI: Join RP, SP and PQ.

Thus PQRS is the required quadrilateral.

Question 2.

Construct a quadrilateral ABCD in which AB = 4 cm, BC = 3.5 cm, CD = 5 cm, AD = 5.5 cm and ∠B = 75°.

Solution:

Construction:

Step I: Draw AB = 4 cm.

Step II: Draw an angle of 75° at B and cut BC = 3.5 cm.

Step III: Draw an arc with centre C and radius 5 cm.

Step IV: Draw another arc with centre A and radius 5.5 cm to meet the previous arc at D.

Step V: Join CD and AD.

Thus ABCD is the required quadrilateral.

Question 3.

Construct a square whose side is 5 cm.

Solution:

Construction:

Step I: Draw AB = 5 cm.

Step II: Draw an angle of 90° at B and cut BC = 5 cm.

Step III: Draw two arcs with centre A and C and same radii of 5 cm which meet each other at D.

Step IV: Join AD and CD.

Thus, ABCD is the required square.

Question 4.

Construct a rhombus ABCD in which AB = 5.8 cm and AC = 7.5 cm.

Solution:

Construction:

Step I: Draw AB = 5.8 cm.

Step II: Draw an arc with centre B and radius 5.8 cm.

Step III: Draw another arc with centre A and radius 7.5 cm to meet the previous arc at C.

Step IV: Draw two arcs with centres A and C and of the same radius 5.8 cm to meet each other at D.

Step V: Join BC, AC, CD and AD.

Thus ABCD is the required rhombus.

Question 5.

Construct a rhombus whose diagonals are 6 cm and 8 cm.

Solution:

Construction:

Step I: Draw SQ = 8 cm.

Step II: Draw a right bisector of SQ at O.

Step III: Draw two arcs with centre O and radius 3 cm each to cut the right bisector at P and R.

Step TV: Join PQ, QR, RS and SP.

Thus PQRS is the required rhombus.

Question 6.

Construct a rectangle whose diagonal is 5 cm and the angle between the diagonal is 50°.

Solution:

Construction:

Step I: Draw AC = 5 cm.

Step II: Draw the right bisector of AC at O.

Step III: Draw an angle of 50° at O and product both sides.

Step IV: Draw two arcs with centre O and of the same radius 2.5 cm to cut at B and D.

Step V: Join AB, BC, CD and DA.

Thus, ABCD is the required rectangle.

Question 7.

Construct a quadrilateral ABCD in which BC = 4 cm, ∠B = 60°, ∠C = 135°, AB = 5 cm and ∠A = 90°.

Solution:

Construction:

Step I: Draw AB = 5 cm.

Step II: Draw the angle of 60° at B and cut BC = 4 cm.

Step III: Draw an angle of 135° at C and angle of 90° at A which meet each other at D.

Thus, ABCD is the required quadrilateral.

Question 8.

Construct a parallelogram ABCD in which AB = 5.5 cm, AC = 7 cm and BD = 8 cm.

Solution:

Construction:

Step I: Draw AB = 5.5 cm.

Step II: Draw an arc with centre B and radius cm = 4 cm.

Step III: Draw another arc with centre A and radius cm = 3.5 cm which cuts the previous arc at O.

Step IV: Join AO and produce to C such that AO = OC.

Step V: Join BO and produce to D such that BO = OD.

Step VI: Join BC, CD and AD.

Thus ABCD is the required parallelogram.

Question 9.

Construct a rhombus PAIR, given that PA = 6 cm and angle ∠A = 110°.

Solution:

Since in a rhombus, all sides are equal, so PA = AI = IR = RP = 6 cm

Also, rhombus is a parallelogram

so, adjacent angle, ∠I = 180° – 110° = 70°

Steps of construction

Step I. Draw AI = 6 cm

Step II. Draw ray such that ∠IAX = 110° and draw such that ∠AIY = 70°.

Step III. With A and I as centres and radius 6 cm draw arcs intersecting AX and IY at P and R respectively.

Step IV. Join PR.

Thus, PAIR is the required rhombus.

## NCERT Solutions for Class 8 Maths

**Chapter 1: Rational Numbers****Chapter 2: Linear Equations in One Variable****Chapter 3: Understanding Quadrilaterals****Chapter 4: Practical Geometry****Chapter 5: Data Handling****Chapter 6: Squares and Square Roots****Chapter 7: Cubes and Cube Roots****Chapter 8: Comparing Quantities****Chapter 9: Algebraic Expressions and Identities****Chapter 10: Visualising Solid Shapes****Chapter 11: Mensuration****Chapter 12: Exponents and Powers****Chapter 13: Direct and Indirect proportions****Chapter 14: Factorisation****Chapter 15: Introduction to Graphs****Chapter 16: Playing with Numbers**